What are the solutions to the equation t^2-16=0 ?

The solutions to the equation t^2-16=0 are t=4,t=-4

Find the zeros of t^2-16=0

The zeros of t^2-16=0 are t=4,t=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t^{2} - 16 = 0

t = 4, t = - 4

Solution steps

t^{2} - 16 = 0

Move

16

to the right side

t^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 16, t = - 16

16 = 4

- 16 = - 4

t = 4, t = - 4

- 3 y + 12 = - 48

x + 8 \geq 6

\frac{5}{3} (- \frac{3}{4} + \frac{1}{2}) = \frac{2}{3} (- \frac{2}{6})

3 x - 6 \geq 9

3 - 2192

What are the solutions to the equation t^2-16=0 ?
The solutions to the equation t^2-16=0 are t=4,t=-4
Find the zeros of t^2-16=0
The zeros of t^2-16=0 are t=4,t=-4