What are the solutions to the equation 8x^2-48x=-104 ?

The solutions to the equation 8x^2-48x=-104 are x=3+2i,x=3-2i

Find the zeros of 8x^2-48x=-104

The zeros of 8x^2-48x=-104 are x=3+2i,x=3-2i

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8 x^{2} - 48 x = - 104

x = 3 + 2 i, x = 3 - 2 i

Solution steps

8 x^{2} - 48 x = - 104

Move

104

to the left side

8 x^{2} - 48 x + 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 8 \cdot 104}{2 \cdot 8}

Simplify

(- 48)^{2} - 4 \cdot 8 \cdot 104 : 32 i

x_{1, 2} = \frac{- ( - 48 ) \pm 32 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 32 i}{2 \cdot 8}, x_{2} = \frac{- ( - 48 ) - 32 i}{2 \cdot 8}

x = \frac{- ( - 48 ) + 32 i}{2 \cdot 8} : 3 + 2 i

x = \frac{- ( - 48 ) - 32 i}{2 \cdot 8} : 3 - 2 i

The solutions to the quadratic equation are:

x = 3 + 2 i, x = 3 - 2 i

(\frac{y ^{2}}{2})^{2}

- \frac{5}{8} \cdot (- 3)

x + 8 = 3 x - 4

x (x + 2) = 3 + x (x - 5)

2 x^{2} + 9 x - 35

What are the solutions to the equation 8x^2-48x=-104 ?
The solutions to the equation 8x^2-48x=-104 are x=3+2i,x=3-2i
Find the zeros of 8x^2-48x=-104
The zeros of 8x^2-48x=-104 are x=3+2i,x=3-2i