What are the solutions to the equation 2x^2-2x-5=0 ?

The solutions to the equation 2x^2-2x-5=0 are x=(1+sqrt(11))/2 ,x=(1-sqrt(11))/2

Find the zeros of 2x^2-2x-5=0

The zeros of 2x^2-2x-5=0 are x=(1+sqrt(11))/2 ,x=(1-sqrt(11))/2

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2 x^{2} - 2 x - 5 = 0

x = \frac{1 + 11}{2}, x = \frac{1 - 11}{2}

Decimal Notation

x = 2.15831 \dots, x = - 1.15831 \dots

Solution steps

2 x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 5) = 211

x_{1, 2} = \frac{- ( - 2 ) \pm 2 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 11}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2 11}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2 11}{2 \cdot 2} : \frac{1 + 11}{2}

x = \frac{- ( - 2 ) - 2 11}{2 \cdot 2} : \frac{1 - 11}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 11}{2}, x = \frac{1 - 11}{2}

5 x + 3 = - 3 x - 1

\frac{n - 9}{n + 9} - \frac{n - 10}{n + 8}

am x^{2} + bm x y - an x y - bn y^{2}

\frac{3 + 3}{3 - 3}

3 (3 x - 3)^{2} + 11 = 41

What are the solutions to the equation 2x^2-2x-5=0 ?
The solutions to the equation 2x^2-2x-5=0 are x=(1+sqrt(11))/2 ,x=(1-sqrt(11))/2
Find the zeros of 2x^2-2x-5=0
The zeros of 2x^2-2x-5=0 are x=(1+sqrt(11))/2 ,x=(1-sqrt(11))/2