What are the solutions to the equation -11s^2+26s+61=0 ?

The solutions to the equation -11s^2+26s+61=0 are s=-(-13+2sqrt(210))/(11),s=(13+2sqrt(210))/(11)

Find the zeros of -11s^2+26s+61=0

The zeros of -11s^2+26s+61=0 are s=-(-13+2sqrt(210))/(11),s=(13+2sqrt(210))/(11)

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- 11 s^{2} + 26 s + 61 = 0

s = - \frac{- 13 + 2 210}{11}, s = \frac{13 + 2 210}{11}

Decimal Notation

s = - 1.45297 \dots, s = 3.81661 \dots

Solution steps

- 11 s^{2} + 26 s + 61 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 ( - 11 ) \cdot 61}{2 ( - 11 )}

2 6^{2} - 4 (- 11) \cdot 61 = 4210

s_{1, 2} = \frac{- 26 \pm 4 210}{2 ( - 11 )}

Separate the solutions

s_{1} = \frac{- 26 + 4 210}{2 ( - 11 )}, s_{2} = \frac{- 26 - 4 210}{2 ( - 11 )}

s = \frac{- 26 + 4 210}{2 ( - 11 )} : - \frac{- 13 + 2 210}{11}

s = \frac{- 26 - 4 210}{2 ( - 11 )} : \frac{13 + 2 210}{11}

The solutions to the quadratic equation are:

s = - \frac{- 13 + 2 210}{11}, s = \frac{13 + 2 210}{11}

(12 mn) (- m^{3} n^{- 2} p^{5}) (2 m)

3 (2 y - 3) = 7

x^{2} + x y - 5 x - 5 y

4 - x^{2} > x + 7

0.6 x^{2} - 1.5 x + 1 = 0

What are the solutions to the equation -11s^2+26s+61=0 ?
The solutions to the equation -11s^2+26s+61=0 are s=-(-13+2sqrt(210))/(11),s=(13+2sqrt(210))/(11)
Find the zeros of -11s^2+26s+61=0
The zeros of -11s^2+26s+61=0 are s=-(-13+2sqrt(210))/(11),s=(13+2sqrt(210))/(11)