What are the solutions to the equation 0.6x^2-1.5x+1=0 ?

The solutions to the equation 0.6x^2-1.5x+1=0 are x= 5/4+i(sqrt(15))/(12),x= 5/4-i(sqrt(15))/(12)

Find the zeros of 0.6x^2-1.5x+1=0

The zeros of 0.6x^2-1.5x+1=0 are x= 5/4+i(sqrt(15))/(12),x= 5/4-i(sqrt(15))/(12)

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0.6 x^{2} - 1.5 x + 1 = 0

x = \frac{5}{4} + i \frac{15}{12}, x = \frac{5}{4} - i \frac{15}{12}

Solution steps

0.6 x^{2} - 1.5 x + 1 = 0

Multiply both sides by

10

6 x^{2} - 15 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 6 \cdot 10}{2 \cdot 6}

Simplify

(- 15)^{2} - 4 \cdot 6 \cdot 10 : 15 i

x_{1, 2} = \frac{- ( - 15 ) \pm 15 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 15 i}{2 \cdot 6}, x_{2} = \frac{- ( - 15 ) - 15 i}{2 \cdot 6}

x = \frac{- ( - 15 ) + 15 i}{2 \cdot 6} : \frac{5}{4} + i \frac{15}{12}

x = \frac{- ( - 15 ) - 15 i}{2 \cdot 6} : \frac{5}{4} - i \frac{15}{12}

The solutions to the quadratic equation are:

x = \frac{5}{4} + i \frac{15}{12}, x = \frac{5}{4} - i \frac{15}{12}

\frac{3 + 2}{1 - 3}

\frac{3 a}{8} - 2 = \frac{2 a + 9}{5}

- 4 x^{2} + 4 x - 1

x^{2} + \frac{3}{2} x + \frac{1}{2} = 0

x^{2} + x = 1.5 x^{2}

What are the solutions to the equation 0.6x^2-1.5x+1=0 ?
The solutions to the equation 0.6x^2-1.5x+1=0 are x= 5/4+i(sqrt(15))/(12),x= 5/4-i(sqrt(15))/(12)
Find the zeros of 0.6x^2-1.5x+1=0
The zeros of 0.6x^2-1.5x+1=0 are x= 5/4+i(sqrt(15))/(12),x= 5/4-i(sqrt(15))/(12)