What is sqrt(y-7)+5>= 10 ?

The solution to sqrt(y-7)+5>= 10 is y>= 32

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sqrt(y-7)+5>= 10

y - 7 + 5 \geq 10

y \geq 32

Interval Notation

[32, \infty)

Solution steps

y - 7 + 5 \geq 10

Move

5

to the right side

y - 7 \geq 5

Square both sides

(y - 7)^{2} \geq 5^{2}

Simplify

y - 7 \geq 25

Move

7

to the right side

y \geq 32

Find singularity points

Find non-negative values for radicals:

y \geq 7

Combine the intervals

y \geq 32 and y \geq 7

Merge Overlapping Intervals

y \geq 32

n - 10 + 9 n - 3

\frac{( x ^{2} - 4 )}{4} = \frac{( 3 + 2 x )}{2}

\frac{1}{2} \cdot \frac{1}{10}

\frac{2}{3} + (- \frac{3}{4}) - \frac{1}{2}

\frac{1}{2} (e^{2} - \frac{1}{e ^{2}})