What are the solutions to the equation x^2-0.95x+0.12=0 ?

The solutions to the equation x^2-0.95x+0.12=0 are x= 4/5 ,x= 3/20

Find the zeros of x^2-0.95x+0.12=0

The zeros of x^2-0.95x+0.12=0 are x= 4/5 ,x= 3/20

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x^{2} - 0.95 x + 0.12 = 0

x = \frac{4}{5}, x = \frac{3}{20}

Decimal Notation

x = 0.8, x = 0.15

Solution steps

x^{2} - 0.95 x + 0.12 = 0

Multiply both sides by

100

100 x^{2} - 95 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 95 ) \pm ( - 95 ) ^{2} - 4 \cdot 100 \cdot 12}{2 \cdot 100}

(- 95)^{2} - 4 \cdot 100 \cdot 12 = 65

x_{1, 2} = \frac{- ( - 95 ) \pm 65}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 95 ) + 65}{2 \cdot 100}, x_{2} = \frac{- ( - 95 ) - 65}{2 \cdot 100}

x = \frac{- ( - 95 ) + 65}{2 \cdot 100} : \frac{4}{5}

x = \frac{- ( - 95 ) - 65}{2 \cdot 100} : \frac{3}{20}

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = \frac{3}{20}

\frac{11}{18} - \frac{7}{18}

2 x^{2} - 3 x - 2 \leq 0

48 x^{3} + 8 x^{4}

4 (3 x - 1) \leq 5 (2 x - 4)

\frac{1}{2} \cdot 0.0039 \cdot v^{2} = 0.0045

What are the solutions to the equation x^2-0.95x+0.12=0 ?
The solutions to the equation x^2-0.95x+0.12=0 are x= 4/5 ,x= 3/20
Find the zeros of x^2-0.95x+0.12=0
The zeros of x^2-0.95x+0.12=0 are x= 4/5 ,x= 3/20