What are the solutions to the equation (-3/5)^2+y^2=1 ?

The solutions to the equation (-3/5)^2+y^2=1 are y= 4/5 ,y=-4/5

Find the zeros of (-3/5)^2+y^2=1

The zeros of (-3/5)^2+y^2=1 are y= 4/5 ,y=-4/5

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(- \frac{3}{5})^{2} + y^{2} = 1

y = \frac{4}{5}, y = - \frac{4}{5}

Decimal Notation

y = 0.8, y = - 0.8

Solution steps

(- \frac{3}{5})^{2} + y^{2} = 1

Expand

(- \frac{3}{5})^{2} + y^{2} : \frac{9}{25} + y^{2}

\frac{9}{25} + y^{2} = 1

Move

\frac{9}{25}

to the right side

y^{2} = 1 - \frac{9}{25}

Simplify

1 - \frac{9}{25} : \frac{16}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{16}{25}, y = - \frac{16}{25}

\frac{16}{25} = \frac{4}{5}

- \frac{16}{25} = - \frac{4}{5}

y = \frac{4}{5}, y = - \frac{4}{5}

3 (x - 7) = 5 (x - 1) - 4

2 - 23

\frac{k + 1}{k + 2} + \frac{1}{( k + 1 ) ( k + 2 )}

2 x < 3 x + 2 < x + 6

2 x + 4 \leq 5 x + 3

What are the solutions to the equation (-3/5)^2+y^2=1 ?
The solutions to the equation (-3/5)^2+y^2=1 are y= 4/5 ,y=-4/5
Find the zeros of (-3/5)^2+y^2=1
The zeros of (-3/5)^2+y^2=1 are y= 4/5 ,y=-4/5