What are the solutions to the equation 47m^2+88m+39=0 ?

The solutions to the equation 47m^2+88m+39=0 are m=(-44+sqrt(103))/(47),m=-(44+sqrt(103))/(47)

Find the zeros of 47m^2+88m+39=0

The zeros of 47m^2+88m+39=0 are m=(-44+sqrt(103))/(47),m=-(44+sqrt(103))/(47)

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47 m^{2} + 88 m + 39 = 0

m = \frac{- 44 + 103}{47}, m = - \frac{44 + 103}{47}

Decimal Notation

m = - 0.72023 \dots, m = - 1.15210 \dots

Solution steps

47 m^{2} + 88 m + 39 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 88 \pm 8 8 ^{2} - 4 \cdot 47 \cdot 39}{2 \cdot 47}

8 8^{2} - 4 \cdot 47 \cdot 39 = 2103

m_{1, 2} = \frac{- 88 \pm 2 103}{2 \cdot 47}

Separate the solutions

m_{1} = \frac{- 88 + 2 103}{2 \cdot 47}, m_{2} = \frac{- 88 - 2 103}{2 \cdot 47}

m = \frac{- 88 + 2 103}{2 \cdot 47} : \frac{- 44 + 103}{47}

m = \frac{- 88 - 2 103}{2 \cdot 47} : - \frac{44 + 103}{47}

The solutions to the quadratic equation are:

m = \frac{- 44 + 103}{47}, m = - \frac{44 + 103}{47}

(\frac{1}{3})^{4}

9 v + 2 \geq 6 v + 8 or - 10 - 8 v > 3 v - 10

\frac{\frac{1}{2}}{\frac{1}{2}}

- 3 = a - 11

\frac{3}{2} - \frac{1}{3}

What are the solutions to the equation 47m^2+88m+39=0 ?
The solutions to the equation 47m^2+88m+39=0 are m=(-44+sqrt(103))/(47),m=-(44+sqrt(103))/(47)
Find the zeros of 47m^2+88m+39=0
The zeros of 47m^2+88m+39=0 are m=(-44+sqrt(103))/(47),m=-(44+sqrt(103))/(47)