What are the solutions to the equation x^2+10^2=26^2 ?

The solutions to the equation x^2+10^2=26^2 are x=24,x=-24

Find the zeros of x^2+10^2=26^2

The zeros of x^2+10^2=26^2 are x=24,x=-24

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x^{2} + 1 0^{2} = 2 6^{2}

x = 24, x = - 24

Solution steps

x^{2} + 1 0^{2} = 2 6^{2}

Move

1 0^{2}

to the right side

x^{2} = 576

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 576, x = - 576

576 = 24

- 576 = - 24

x = 24, x = - 24

2 x + 1 > 3

\frac{( 3 x y ) ^{2} ( 2 x ^{4} y ^{3} )}{6 x ^{8} y}

\frac{12}{5 y ^{2}} - \frac{2}{5 yz}

2 (- 27)^{\frac{8}{3}}

4 d - 1 > - 3

What are the solutions to the equation x^2+10^2=26^2 ?
The solutions to the equation x^2+10^2=26^2 are x=24,x=-24
Find the zeros of x^2+10^2=26^2
The zeros of x^2+10^2=26^2 are x=24,x=-24