What are the solutions to the equation a^2+sqrt(7)^2=6^2 ?

The solutions to the equation a^2+sqrt(7)^2=6^2 are a=sqrt(29),a=-sqrt(29)

Find the zeros of a^2+sqrt(7)^2=6^2

The zeros of a^2+sqrt(7)^2=6^2 are a=sqrt(29),a=-sqrt(29)

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a^{2} + 7^{2} = 6^{2}

a = 29, a = - 29

Decimal Notation

a = 5.38516 \dots, a = - 5.38516 \dots

Solution steps

a^{2} + (7)^{2} = 6^{2}

Move

7^{2}

to the right side

a^{2} = 29

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 29, a = - 29

(x - 2 - x^{2}) (x^{2} + 2 x - 8) < 0

0^{- \frac{1}{2}}

- \frac{3}{4} - 1

\frac{1350}{600}

- \frac{39}{56} - \frac{22}{35}

What are the solutions to the equation a^2+sqrt(7)^2=6^2 ?
The solutions to the equation a^2+sqrt(7)^2=6^2 are a=sqrt(29),a=-sqrt(29)
Find the zeros of a^2+sqrt(7)^2=6^2
The zeros of a^2+sqrt(7)^2=6^2 are a=sqrt(29),a=-sqrt(29)