What are the solutions to the equation x^2+18x=-56 ?

The solutions to the equation x^2+18x=-56 are x=-4,x=-14

Find the zeros of x^2+18x=-56

The zeros of x^2+18x=-56 are x=-4,x=-14

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x^{2} + 18 x = - 56

x = - 4, x = - 14

Solution steps

x^{2} + 18 x = - 56

Move

56

to the left side

x^{2} + 18 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 56 = 10

x_{1, 2} = \frac{- 18 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 10}{2 \cdot 1}, x_{2} = \frac{- 18 - 10}{2 \cdot 1}

x = \frac{- 18 + 10}{2 \cdot 1} : - 4

x = \frac{- 18 - 10}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = - 4, x = - 14

5 x - 102 = 13

(0.00074 x)^{2}

\frac{9 + 2}{4 - 7}

- 1 < 7 - 5 x < 2

What are the solutions to the equation x^2+18x=-56 ?
The solutions to the equation x^2+18x=-56 are x=-4,x=-14
Find the zeros of x^2+18x=-56
The zeros of x^2+18x=-56 are x=-4,x=-14