What are the solutions to the equation 5x^2+15x-20=0 ?

The solutions to the equation 5x^2+15x-20=0 are x=1,x=-4

Find the zeros of 5x^2+15x-20=0

The zeros of 5x^2+15x-20=0 are x=1,x=-4

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5 x^{2} + 15 x - 20 = 0

x = 1, x = - 4

Solution steps

5 x^{2} + 15 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 ( - 20 )}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 (- 20) = 25

x_{1, 2} = \frac{- 15 \pm 25}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 15 + 25}{2 \cdot 5}, x_{2} = \frac{- 15 - 25}{2 \cdot 5}

x = \frac{- 15 + 25}{2 \cdot 5} : 1

x = \frac{- 15 - 25}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

7 - y = \frac{( y - 4 ) ^{2}}{4}

lo g_{36} (\frac{1}{6}) = x

x^{8} - 16

x^{2} + 14 x = 2 x - 32

5 = ∣ 2 z + 3 ∣

What are the solutions to the equation 5x^2+15x-20=0 ?
The solutions to the equation 5x^2+15x-20=0 are x=1,x=-4
Find the zeros of 5x^2+15x-20=0
The zeros of 5x^2+15x-20=0 are x=1,x=-4