What is sqrt(x-4)<= 0 ?

The solution to sqrt(x-4)<= 0 is x=4

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sqrt(x-4)<= 0

x - 4 \leq 0

x = 4

Interval Notation

x = 4

Solution steps

x - 4 \leq 0

Square both sides

(x - 4)^{2} \leq 0^{2}

Simplify

x - 4 \leq 0

Move

4

to the right side

x \leq 4

Find singularity points

Find non-negative values for radicals:

x \geq 4

Combine the intervals

x \leq 4 and x \geq 4

Merge Overlapping Intervals

x = 4

8 n - 10 < 6 - 2 n

x^{3} y^{2} - 2 x^{3} y

0.25

27 + 37

35 x^{4} - 15 x^{2} + 70 x^{2} - 30 x