What are the solutions to the equation 10^2+24^2=c^2 ?

The solutions to the equation 10^2+24^2=c^2 are c=26,c=-26

Find the zeros of 10^2+24^2=c^2

The zeros of 10^2+24^2=c^2 are c=26,c=-26

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1 0^{2} + 2 4^{2} = c^{2}

c = 26, c = - 26

Solution steps

1 0^{2} + 2 4^{2} = c^{2}

Switch sides

c^{2} = 1 0^{2} + 2 4^{2}

Simplify

1 0^{2} + 2 4^{2} : 676

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 676, c = - 676

676 = 26

- 676 = - 26

c = 26, c = - 26

9^{2} + 7^{2} = c^{2}

5 a (- 3 b) (- 2 a^{2} b^{3})

\frac{k}{k + 1} + \frac{1}{( k + 1 ) ( k + 2 )}

53 = 8 + 0.07 t

\frac{\frac{10000}{\frac{1}{100}}}{1000}

What are the solutions to the equation 10^2+24^2=c^2 ?
The solutions to the equation 10^2+24^2=c^2 are c=26,c=-26
Find the zeros of 10^2+24^2=c^2
The zeros of 10^2+24^2=c^2 are c=26,c=-26