What are the solutions to the equation 7x^2-112=0 ?

The solutions to the equation 7x^2-112=0 are x=4,x=-4

Find the zeros of 7x^2-112=0

The zeros of 7x^2-112=0 are x=4,x=-4

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7 x^{2} - 112 = 0

x = 4, x = - 4

Solution steps

7 x^{2} - 112 = 0

Move

112

to the right side

7 x^{2} = 112

Divide both sides by

7

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

(47 + 3) (67 - 1)

x^{3} + 5 x^{2} + 8 x + 4

7 (3 x + 9) = 11 - (x + 3)

- \frac{3}{4 ^{2}}

5 - 8 w \leq 11 - 6 w

What are the solutions to the equation 7x^2-112=0 ?
The solutions to the equation 7x^2-112=0 are x=4,x=-4
Find the zeros of 7x^2-112=0
The zeros of 7x^2-112=0 are x=4,x=-4