What is (9/20 d^5)(2d^{-2})(4/3 d^9) ?

The solution to (9/20 d^5)(2d^{-2})(4/3 d^9) is (6d^{12})/5

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simplify (9/20 d^5)(2d^{-2})(4/3 d^9)

simplify

(\frac{9}{20} d^{5}) (2 d^{- 2}) (\frac{4}{3} d^{9})

\frac{6 d ^{12}}{5}

Solution steps

(\frac{9}{20} d^{5}) (2 d^{- 2}) (\frac{4}{3} d^{9})

Simplify

2 d^{- 2} : \frac{2}{d ^{2}}

= \frac{9}{20} d^{5} \frac{2}{d ^{2}} \cdot \frac{4}{3} d^{9}

Simplify

d^{5} d^{9} : d^{14}

= \frac{9}{20} d^{14} \frac{2}{d ^{2}} \cdot \frac{4}{3}

= \frac{9}{20} \cdot \frac{4}{3} d^{14} \frac{2}{d ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{9 \cdot 4 d ^{14} \cdot 2}{20 \cdot 3 d ^{2}}

Factor the number:

9 = 3 \cdot 3

= \frac{3 \cdot 3 \cdot 4 d ^{14} \cdot 2}{20 \cdot 3 d ^{2}}

Cancel the common factor:

3

= \frac{3 \cdot 4 d ^{14} \cdot 2}{20 d ^{2}}

Factor the number:

20 = 4 \cdot 5

= \frac{3 \cdot 4 d ^{14} \cdot 2}{4 \cdot 5 d ^{2}}

Cancel the common factor:

4

= \frac{3 d ^{14} \cdot 2}{5 d ^{2}}

Simplify

\frac{d ^{14}}{d ^{2}} : d^{12}

= \frac{3 d ^{12} \cdot 2}{5}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{6 d ^{12}}{5}

0. 5^{0.5}

(- 3 + i) (- 3 - i)

3 x^{2} - 3 = 0

\frac{1}{3} x = - \frac{4}{5}

5 y^{2} - 8 y = 2

What is (9/20 d^5)(2d^{-2})(4/3 d^9) ?
The solution to (9/20 d^5)(2d^{-2})(4/3 d^9) is (6d^{12})/5