What are the solutions to the equation u^2+8u+16=0 ?

The solutions to the equation u^2+8u+16=0 are u=-4

Find the zeros of u^2+8u+16=0

The zeros of u^2+8u+16=0 are u=-4

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u^{2} + 8 u + 16 = 0

u = - 4

Solution steps

u^{2} + 8 u + 16 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

u_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

u = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

u = - 4

The solution to the quadratic equation is:

u = - 4

36 x - 27

(\frac{1}{7})^{- 4}

- 6 (x + 1) = 2 (1 - 3 x) - 8

- 4 - 5 R + 14 = R + 6 + 2 R

3 m^{2} n + 12 m n^{2}

What are the solutions to the equation u^2+8u+16=0 ?
The solutions to the equation u^2+8u+16=0 are u=-4
Find the zeros of u^2+8u+16=0
The zeros of u^2+8u+16=0 are u=-4