What are the solutions to the equation x^2-20x+98=0 ?

The solutions to the equation x^2-20x+98=0 are x=10+sqrt(2),x=10-sqrt(2)

Find the zeros of x^2-20x+98=0

The zeros of x^2-20x+98=0 are x=10+sqrt(2),x=10-sqrt(2)

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x^{2} - 20 x + 98 = 0

x = 10 + 2, x = 10 - 2

Decimal Notation

x = 11.41421 \dots, x = 8.58578 \dots

Solution steps

x^{2} - 20 x + 98 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 98}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 98 = 22

x_{1, 2} = \frac{- ( - 20 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2 2}{2 \cdot 1} : 10 + 2

x = \frac{- ( - 20 ) - 2 2}{2 \cdot 1} : 10 - 2

The solutions to the quadratic equation are:

x = 10 + 2, x = 10 - 2

\frac{8}{3} + \frac{5}{6}

25 x^{2} - 10 x + 1

a^{2} - 4 a - 45

x + 1 = 2 x + 2

lo g_{3} (16)

What are the solutions to the equation x^2-20x+98=0 ?
The solutions to the equation x^2-20x+98=0 are x=10+sqrt(2),x=10-sqrt(2)
Find the zeros of x^2-20x+98=0
The zeros of x^2-20x+98=0 are x=10+sqrt(2),x=10-sqrt(2)