What are the solutions to the equation 6x+7-x^2=0 ?

The solutions to the equation 6x+7-x^2=0 are x=-1,x=7

Find the zeros of 6x+7-x^2=0

The zeros of 6x+7-x^2=0 are x=-1,x=7

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6 x + 7 - x^{2} = 0

x = - 1, x = 7

Solution steps

6 x + 7 - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 7 = 8

x_{1, 2} = \frac{- 6 \pm 8}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 8}{2 ( - 1 )}, x_{2} = \frac{- 6 - 8}{2 ( - 1 )}

x = \frac{- 6 + 8}{2 ( - 1 )} : - 1

x = \frac{- 6 - 8}{2 ( - 1 )} : 7

The solutions to the quadratic equation are:

x = - 1, x = 7

\frac{x ^{4}}{x ^{2}}

4 x^{2} + 9 x + 5 = 0

\frac{m ^{- \frac{5}{2}}}{m ^{- 2}}

4 + 2 k > 8

4 x^{2} + 3 x - 10

What are the solutions to the equation 6x+7-x^2=0 ?
The solutions to the equation 6x+7-x^2=0 are x=-1,x=7
Find the zeros of 6x+7-x^2=0
The zeros of 6x+7-x^2=0 are x=-1,x=7