What are the solutions to the equation 12x^2-3x=0 ?

The solutions to the equation 12x^2-3x=0 are x= 1/4 ,x=0

Find the zeros of 12x^2-3x=0

The zeros of 12x^2-3x=0 are x= 1/4 ,x=0

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12 x^{2} - 3 x = 0

x = \frac{1}{4}, x = 0

Decimal Notation

x = 0.25, x = 0

Solution steps

12 x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

(- 3)^{2} - 4 \cdot 12 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 12}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 12}

x = \frac{- ( - 3 ) + 3}{2 \cdot 12} : \frac{1}{4}

x = \frac{- ( - 3 ) - 3}{2 \cdot 12} : 0

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 0

- 2 k = k - 7 - 8

x^{2} + 3 x - 28 > 0

2 x^{2} - 4 x - 126

x^{2} + 4 - 12

What are the solutions to the equation 12x^2-3x=0 ?
The solutions to the equation 12x^2-3x=0 are x= 1/4 ,x=0
Find the zeros of 12x^2-3x=0
The zeros of 12x^2-3x=0 are x= 1/4 ,x=0