What are the solutions to the equation x^2-18x+209=2x+11 ?

The solutions to the equation x^2-18x+209=2x+11 are x=10+7sqrt(2)i,x=10-7sqrt(2)i

Find the zeros of x^2-18x+209=2x+11

The zeros of x^2-18x+209=2x+11 are x=10+7sqrt(2)i,x=10-7sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 18 x + 209 = 2 x + 11

x = 10 + 72 i, x = 10 - 72 i

Solution steps

x^{2} - 18 x + 209 = 2 x + 11

Move

11

to the left side

x^{2} - 18 x + 198 = 2 x

Move

2 x

to the left side

x^{2} - 20 x + 198 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 198}{2 \cdot 1}

Simplify

(- 20)^{2} - 4 \cdot 1 \cdot 198 : 142 i

x_{1, 2} = \frac{- ( - 20 ) \pm 14 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 14 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 14 2 i}{2 \cdot 1}

x = \frac{- ( - 20 ) + 14 2 i}{2 \cdot 1} : 10 + 72 i

x = \frac{- ( - 20 ) - 14 2 i}{2 \cdot 1} : 10 - 72 i

The solutions to the quadratic equation are:

x = 10 + 72 i, x = 10 - 72 i

x^{2} = 676

6 < x \leq 8

x - \frac{1}{3} \geq - \frac{3}{2}

0 = (x - 4)^{2}

\frac{3}{8 i}

What are the solutions to the equation x^2-18x+209=2x+11 ?
The solutions to the equation x^2-18x+209=2x+11 are x=10+7sqrt(2)i,x=10-7sqrt(2)i
Find the zeros of x^2-18x+209=2x+11
The zeros of x^2-18x+209=2x+11 are x=10+7sqrt(2)i,x=10-7sqrt(2)i