What are the solutions to the equation x^2-2x+7=0 ?

The solutions to the equation x^2-2x+7=0 are x=1+sqrt(6)i,x=1-sqrt(6)i

Find the zeros of x^2-2x+7=0

The zeros of x^2-2x+7=0 are x=1+sqrt(6)i,x=1-sqrt(6)i

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x^{2} - 2 x + 7 = 0

x = 1 + 6 i, x = 1 - 6 i

Solution steps

x^{2} - 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 7 : 26 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 6 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 6 i}{2 \cdot 1} : 1 + 6 i

x = \frac{- ( - 2 ) - 2 6 i}{2 \cdot 1} : 1 - 6 i

The solutions to the quadratic equation are:

x = 1 + 6 i, x = 1 - 6 i

(\frac{3 x ^{4}}{2 y ^{5}})^{- 3}

36 - w^{2}

x \leq 15 - 2 x^{2}

(- x - 1) (- x - 1)

7 = \frac{k}{2}

What are the solutions to the equation x^2-2x+7=0 ?
The solutions to the equation x^2-2x+7=0 are x=1+sqrt(6)i,x=1-sqrt(6)i
Find the zeros of x^2-2x+7=0
The zeros of x^2-2x+7=0 are x=1+sqrt(6)i,x=1-sqrt(6)i