What are the solutions to the equation 45m^2+18m+1=0 ?

The solutions to the equation 45m^2+18m+1=0 are m=-1/15 ,m=-1/3

Find the zeros of 45m^2+18m+1=0

The zeros of 45m^2+18m+1=0 are m=-1/15 ,m=-1/3

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45 m^{2} + 18 m + 1 = 0

m = - \frac{1}{15}, m = - \frac{1}{3}

Decimal Notation

m = - 0.06666 \dots, m = - 0.33333 \dots

Solution steps

45 m^{2} + 18 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 45 \cdot 1}{2 \cdot 45}

1 8^{2} - 4 \cdot 45 \cdot 1 = 12

m_{1, 2} = \frac{- 18 \pm 12}{2 \cdot 45}

Separate the solutions

m_{1} = \frac{- 18 + 12}{2 \cdot 45}, m_{2} = \frac{- 18 - 12}{2 \cdot 45}

m = \frac{- 18 + 12}{2 \cdot 45} : - \frac{1}{15}

m = \frac{- 18 - 12}{2 \cdot 45} : - \frac{1}{3}

The solutions to the quadratic equation are:

m = - \frac{1}{15}, m = - \frac{1}{3}

x^{2} - 3 x - 18 \geq 0

6 > 8 x + 30

2 a^{2} + 98 = 0

v^{2} - 2 v - 15 = 0

22 - 2

What are the solutions to the equation 45m^2+18m+1=0 ?
The solutions to the equation 45m^2+18m+1=0 are m=-1/15 ,m=-1/3
Find the zeros of 45m^2+18m+1=0
The zeros of 45m^2+18m+1=0 are m=-1/15 ,m=-1/3