What is 2<= 3(3-2x)<= 5 ?

The solution to 2<= 3(3-2x)<= 5 is 2/3 <= x<= 7/6

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2<= 3(3-2x)<= 5

2 \leq 3 (3 - 2 x) \leq 5

\frac{2}{3} \leq x \leq \frac{7}{6}

Interval Notation

[\frac{2}{3}, \frac{7}{6}]

Decimal Notation

0.66666 \dots \leq x \leq 1.16666 \dots

Solution steps

2 \leq 3 (3 - 2 x) \leq 5

a \leq u \leq b

then

a \leq u and u \leq b

2 \leq 3 (3 - 2 x) and 3 (3 - 2 x) \leq 5

2 \leq 3 (3 - 2 x) : x \leq \frac{7}{6}

3 (3 - 2 x) \leq 5 : x \geq \frac{2}{3}

Combine the intervals

x \leq \frac{7}{6} and x \geq \frac{2}{3}

Merge Overlapping Intervals

\frac{2}{3} \leq x \leq \frac{7}{6}

- 16 x^{2} + 40 x - 25 < 0

f = 2^{- 2}

2 s t^{4} - 8 s t^{2} - 90 s

x^{3} + x \geq 2

2 (2 x + x) - (6 - 7 x) = 13 x - (1 + 4 x)