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Popular >

2x^2+8x>= 4x-8

Solution

2 x^{2} + 8 x \geq 4 x - 8

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

2 x^{2} + 8 x \geq 4 x - 8

Rewrite in standard form

x^{2} + 2 x + 4 \geq 0

Complete the square

x^{2} + 2 x + 4 : (x + 1)^{2} + 3

(x + 1)^{2} + 3 \geq 0

Move

3

to the right side

(x + 1)^{2} \geq - 3

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

2x^2+4x-5=2(x-1)

2 x^{2} + 4 x - 5 = 2 (x - 1)

1/4 (12m+28)=6+2(3m+1)

\frac{1}{4} (12 m + 28) = 6 + 2 (3 m + 1)

simplify ln(e^{sqrt(2)})simplify

ln (e^{2})

factor x^3+3x factor

x^{3} + 3 x

simplify (15a-b)/(12a)-(a-4b)/(9a)simplify

\frac{15 a - b}{12 a} - \frac{a - 4 b}{9 a}

Frequently Asked Questions (FAQ)

What is 2x^2+8x>= 4x-8 ?
The solution to 2x^2+8x>= 4x-8 is True for all x