What are the solutions to the equation 3x^2+2x+3=0 ?

The solutions to the equation 3x^2+2x+3=0 are x=-1/3+i(2sqrt(2))/3 ,x=-1/3-i(2sqrt(2))/3

Find the zeros of 3x^2+2x+3=0

The zeros of 3x^2+2x+3=0 are x=-1/3+i(2sqrt(2))/3 ,x=-1/3-i(2sqrt(2))/3

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3 x^{2} + 2 x + 3 = 0

x = - \frac{1}{3} + i \frac{2 2}{3}, x = - \frac{1}{3} - i \frac{2 2}{3}

Solution steps

3 x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

Simplify

2^{2} - 4 \cdot 3 \cdot 3 : 42 i

x_{1, 2} = \frac{- 2 \pm 4 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 4 2 i}{2 \cdot 3}, x_{2} = \frac{- 2 - 4 2 i}{2 \cdot 3}

x = \frac{- 2 + 4 2 i}{2 \cdot 3} : - \frac{1}{3} + i \frac{2 2}{3}

x = \frac{- 2 - 4 2 i}{2 \cdot 3} : - \frac{1}{3} - i \frac{2 2}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{2 2}{3}, x = - \frac{1}{3} - i \frac{2 2}{3}

(2.8 \cdot 1 0^{- 13}) = x (0.013 + x)

10 x + x^{2} = 24

\frac{3 + 4 i}{5 i}

\frac{5}{2} + \frac{1}{4}

25 6^{\frac{- 3}{4}}

What are the solutions to the equation 3x^2+2x+3=0 ?
The solutions to the equation 3x^2+2x+3=0 are x=-1/3+i(2sqrt(2))/3 ,x=-1/3-i(2sqrt(2))/3
Find the zeros of 3x^2+2x+3=0
The zeros of 3x^2+2x+3=0 are x=-1/3+i(2sqrt(2))/3 ,x=-1/3-i(2sqrt(2))/3