What are the solutions to the equation 11x^2+10=13 ?

The solutions to the equation 11x^2+10=13 are x=sqrt(3/11),x=-sqrt(3/11)

Find the zeros of 11x^2+10=13

The zeros of 11x^2+10=13 are x=sqrt(3/11),x=-sqrt(3/11)

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11 x^{2} + 10 = 13

x = \frac{3}{11}, x = - \frac{3}{11}

Decimal Notation

x = 0.52223 \dots, x = - 0.52223 \dots

Solution steps

11 x^{2} + 10 = 13

Move

10

to the right side

11 x^{2} = 3

Divide both sides by

11

x^{2} = \frac{3}{11}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{11}, x = - \frac{3}{11}

- 6 (x + 7)^{2} = - 294

x^{2} + 18 = - 7 x

3 - 7

4 = x^{2} - 3 x

81 x^{4} - 16

What are the solutions to the equation 11x^2+10=13 ?
The solutions to the equation 11x^2+10=13 are x=sqrt(3/11),x=-sqrt(3/11)
Find the zeros of 11x^2+10=13
The zeros of 11x^2+10=13 are x=sqrt(3/11),x=-sqrt(3/11)