What are the solutions to the equation 5w^2+20w=0 ?

The solutions to the equation 5w^2+20w=0 are w=0,w=-4

Find the zeros of 5w^2+20w=0

The zeros of 5w^2+20w=0 are w=0,w=-4

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5 w^{2} + 20 w = 0

w = 0, w = - 4

Solution steps

5 w^{2} + 20 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

2 0^{2} - 4 \cdot 5 \cdot 0 = 20

w_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 5}

Separate the solutions

w_{1} = \frac{- 20 + 20}{2 \cdot 5}, w_{2} = \frac{- 20 - 20}{2 \cdot 5}

w = \frac{- 20 + 20}{2 \cdot 5} : 0

w = \frac{- 20 - 20}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

w = 0, w = - 4

(\frac{4}{5})^{2}

\frac{x + 7}{- 3} = 1

∣ y - 9 ∣ + 7 = 16

x^{2} - 2 x + 2 > 0

(256)^{\frac{1}{4}}

What are the solutions to the equation 5w^2+20w=0 ?
The solutions to the equation 5w^2+20w=0 are w=0,w=-4
Find the zeros of 5w^2+20w=0
The zeros of 5w^2+20w=0 are w=0,w=-4