What are the solutions to the equation 4x^2+3x-4=0 ?

The solutions to the equation 4x^2+3x-4=0 are x=(-3+sqrt(73))/8 ,x=(-3-sqrt(73))/8

Find the zeros of 4x^2+3x-4=0

The zeros of 4x^2+3x-4=0 are x=(-3+sqrt(73))/8 ,x=(-3-sqrt(73))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 3 x - 4 = 0

x = \frac{- 3 + 73}{8}, x = \frac{- 3 - 73}{8}

Decimal Notation

x = 0.69300 \dots, x = - 1.44300 \dots

Solution steps

4 x^{2} + 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 4 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 4) = 73

x_{1, 2} = \frac{- 3 \pm 73}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 73}{2 \cdot 4}, x_{2} = \frac{- 3 - 73}{2 \cdot 4}

x = \frac{- 3 + 73}{2 \cdot 4} : \frac{- 3 + 73}{8}

x = \frac{- 3 - 73}{2 \cdot 4} : \frac{- 3 - 73}{8}

The solutions to the quadratic equation are:

x = \frac{- 3 + 73}{8}, x = \frac{- 3 - 73}{8}

\frac{x}{x - 2} \geq \frac{1}{x}

(- 2.156)^{\frac{1}{3}}

9 x^{2} + 64 x + 7

- 9 x - 17 = - 26

8 p^{2} + 10 p - 3

What are the solutions to the equation 4x^2+3x-4=0 ?
The solutions to the equation 4x^2+3x-4=0 are x=(-3+sqrt(73))/8 ,x=(-3-sqrt(73))/8
Find the zeros of 4x^2+3x-4=0
The zeros of 4x^2+3x-4=0 are x=(-3+sqrt(73))/8 ,x=(-3-sqrt(73))/8