What are the solutions to the equation (x+2)^2-1=0 ?

The solutions to the equation (x+2)^2-1=0 are x=-1,x=-3

Find the zeros of (x+2)^2-1=0

The zeros of (x+2)^2-1=0 are x=-1,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 2)^{2} - 1 = 0

x = - 1, x = - 3

Solution steps

(x + 2)^{2} - 1 = 0

Move

1

to the right side

(x + 2)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 1 : x = - 1

Solve

x + 2 = - 1 : x = - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

x - x^{2} \geq 0

\frac{6 ^{8}}{6 ^{6}}

(- 1 - 2)^{2}

∣ x + 2 ∣ \geq - 7

b - 11 > - 3

What are the solutions to the equation (x+2)^2-1=0 ?
The solutions to the equation (x+2)^2-1=0 are x=-1,x=-3
Find the zeros of (x+2)^2-1=0
The zeros of (x+2)^2-1=0 are x=-1,x=-3