What are the solutions to the equation 4x+2+x^2=0 ?

The solutions to the equation 4x+2+x^2=0 are x=-2+sqrt(2),x=-2-sqrt(2)

Find the zeros of 4x+2+x^2=0

The zeros of 4x+2+x^2=0 are x=-2+sqrt(2),x=-2-sqrt(2)

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4 x + 2 + x^{2} = 0

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

4 x + 2 + x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- 4 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 2}{2 \cdot 1}

x = \frac{- 4 + 2 2}{2 \cdot 1} : - 2 + 2

x = \frac{- 4 - 2 2}{2 \cdot 1} : - 2 - 2

The solutions to the quadratic equation are:

x = - 2 + 2, x = - 2 - 2

2 x^{3} - x^{4} \leq 0

lo g_{\frac{1}{4}} (\frac{1}{16})

\frac{a ^{3} - b ^{3}}{( a - b ) ^{2}} + \frac{3 ab}{b - a}

10 x^{2} + 13 x + 4 = 0

\frac{5}{6} x - \frac{1}{2} = 7

What are the solutions to the equation 4x+2+x^2=0 ?
The solutions to the equation 4x+2+x^2=0 are x=-2+sqrt(2),x=-2-sqrt(2)
Find the zeros of 4x+2+x^2=0
The zeros of 4x+2+x^2=0 are x=-2+sqrt(2),x=-2-sqrt(2)