What are the solutions to the equation x^2-6x-36=0 ?

The solutions to the equation x^2-6x-36=0 are x=3(1+sqrt(5)),x=3(1-sqrt(5))

Find the zeros of x^2-6x-36=0

The zeros of x^2-6x-36=0 are x=3(1+sqrt(5)),x=3(1-sqrt(5))

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x^{2} - 6 x - 36 = 0

x = 3 (1 + 5), x = 3 (1 - 5)

Decimal Notation

x = 9.70820 \dots, x = - 3.70820 \dots

Solution steps

x^{2} - 6 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 36) = 65

x_{1, 2} = \frac{- ( - 6 ) \pm 6 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 5}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 6 5}{2 \cdot 1}

x = \frac{- ( - 6 ) + 6 5}{2 \cdot 1} : 3 (1 + 5)

x = \frac{- ( - 6 ) - 6 5}{2 \cdot 1} : 3 (1 - 5)

The solutions to the quadratic equation are:

x = 3 (1 + 5), x = 3 (1 - 5)

1 - x^{12}

16 z^{2} + 139 = 96 z

\frac{5}{2} (2)^{0}

6 x^{2} - 66 x - 72

\frac{z}{5} + 3 = - 35

What are the solutions to the equation x^2-6x-36=0 ?
The solutions to the equation x^2-6x-36=0 are x=3(1+sqrt(5)),x=3(1-sqrt(5))
Find the zeros of x^2-6x-36=0
The zeros of x^2-6x-36=0 are x=3(1+sqrt(5)),x=3(1-sqrt(5))