What are the solutions to the equation a^2-9a+30=0 ?

The solutions to the equation a^2-9a+30=0 are a= 9/2+i(sqrt(39))/2 ,a= 9/2-i(sqrt(39))/2

Find the zeros of a^2-9a+30=0

The zeros of a^2-9a+30=0 are a= 9/2+i(sqrt(39))/2 ,a= 9/2-i(sqrt(39))/2

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a^{2} - 9 a + 30 = 0

a = \frac{9}{2} + i \frac{39}{2}, a = \frac{9}{2} - i \frac{39}{2}

Solution steps

a^{2} - 9 a + 30 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

Simplify

(- 9)^{2} - 4 \cdot 1 \cdot 30 : 39 i

a_{1, 2} = \frac{- ( - 9 ) \pm 39 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 9 ) + 39 i}{2 \cdot 1}, a_{2} = \frac{- ( - 9 ) - 39 i}{2 \cdot 1}

a = \frac{- ( - 9 ) + 39 i}{2 \cdot 1} : \frac{9}{2} + i \frac{39}{2}

a = \frac{- ( - 9 ) - 39 i}{2 \cdot 1} : \frac{9}{2} - i \frac{39}{2}

The solutions to the quadratic equation are:

a = \frac{9}{2} + i \frac{39}{2}, a = \frac{9}{2} - i \frac{39}{2}

3 r - r = 8

3 \cdot 15

- 3 x < 9 x < x + 6

20 x^{2} - 25 x > 0

\frac{1}{2} x^{2} = - x^{2} + 6

What are the solutions to the equation a^2-9a+30=0 ?
The solutions to the equation a^2-9a+30=0 are a= 9/2+i(sqrt(39))/2 ,a= 9/2-i(sqrt(39))/2
Find the zeros of a^2-9a+30=0
The zeros of a^2-9a+30=0 are a= 9/2+i(sqrt(39))/2 ,a= 9/2-i(sqrt(39))/2