What is x^3+9x^2>= 9x+81 ?

The solution to x^3+9x^2>= 9x+81 is -9 = 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^3+9x^2>= 9x+81

x^{3} + 9 x^{2} \geq 9 x + 81

- 9 \leq x \leq - 3 or x \geq 3

Interval Notation

[- 9, - 3] \cup [3, \infty)

Solution steps

x^{3} + 9 x^{2} \geq 9 x + 81

Rewrite in standard form

x^{3} + 9 x^{2} - 81 - 9 x \geq 0

Factor

x^{3} + 9 x^{2} - 81 - 9 x : (x + 9) (x + 3) (x - 3)

(x + 9) (x + 3) (x - 3) \geq 0

Identify the intervals

- 9 \leq x \leq - 3 or x \geq 3

1600

\frac{9}{- ( \frac{1}{4} ) ^{2}}

- 3 x^{2} - 5 x + 8

\frac{1}{4} π

4 (21) - 12 = c

What is x^3+9x^2>= 9x+81 ?
The solution to x^3+9x^2>= 9x+81 is -9<= x<=-3\lor x>= 3