What are the solutions to the equation (x+2)(x+5)=2x+7 ?

The solutions to the equation (x+2)(x+5)=2x+7 are x=(-5+sqrt(13))/2 ,x=(-5-sqrt(13))/2

Find the zeros of (x+2)(x+5)=2x+7

The zeros of (x+2)(x+5)=2x+7 are x=(-5+sqrt(13))/2 ,x=(-5-sqrt(13))/2

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(x + 2) (x + 5) = 2 x + 7

x = \frac{- 5 + 13}{2}, x = \frac{- 5 - 13}{2}

Decimal Notation

x = - 0.69722 \dots, x = - 4.30277 \dots

Solution steps

(x + 2) (x + 5) = 2 x + 7

Expand

(x + 2) (x + 5) : x^{2} + 7 x + 10

x^{2} + 7 x + 10 = 2 x + 7

Move

7

to the left side

x^{2} + 7 x + 3 = 2 x

Move

2 x

to the left side

x^{2} + 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 3 = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 \cdot 1}, x_{2} = \frac{- 5 - 13}{2 \cdot 1}

x = \frac{- 5 + 13}{2 \cdot 1} : \frac{- 5 + 13}{2}

x = \frac{- 5 - 13}{2 \cdot 1} : \frac{- 5 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 13}{2}, x = \frac{- 5 - 13}{2}

\frac{9}{4} - \frac{4}{3}

2 x^{2} + 18 x + 40

- 2.1 (x + 3.4) = - 3.57

2 (x + 2)^{2} - 5 = 8

8 v - 4 (v + 8) = 8

What are the solutions to the equation (x+2)(x+5)=2x+7 ?
The solutions to the equation (x+2)(x+5)=2x+7 are x=(-5+sqrt(13))/2 ,x=(-5-sqrt(13))/2
Find the zeros of (x+2)(x+5)=2x+7
The zeros of (x+2)(x+5)=2x+7 are x=(-5+sqrt(13))/2 ,x=(-5-sqrt(13))/2