What are the solutions to the equation 9x^2+21x+10=0 ?

The solutions to the equation 9x^2+21x+10=0 are x=-2/3 ,x=-5/3

Find the zeros of 9x^2+21x+10=0

The zeros of 9x^2+21x+10=0 are x=-2/3 ,x=-5/3

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9 x^{2} + 21 x + 10 = 0

x = - \frac{2}{3}, x = - \frac{5}{3}

Decimal Notation

x = - 0.66666 \dots, x = - 1.66666 \dots

Solution steps

9 x^{2} + 21 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 9 \cdot 10}{2 \cdot 9}

2 1^{2} - 4 \cdot 9 \cdot 10 = 9

x_{1, 2} = \frac{- 21 \pm 9}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 21 + 9}{2 \cdot 9}, x_{2} = \frac{- 21 - 9}{2 \cdot 9}

x = \frac{- 21 + 9}{2 \cdot 9} : - \frac{2}{3}

x = \frac{- 21 - 9}{2 \cdot 9} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - \frac{5}{3}

x^{2} - 1 x - 2

(- 7 i)^{2}

\frac{4}{3} + \frac{4}{3}

14 x - 2 (x + 5) < 3 (2 x - 8)

\frac{x y ^{7}}{x ^{3} y ^{4}}

What are the solutions to the equation 9x^2+21x+10=0 ?
The solutions to the equation 9x^2+21x+10=0 are x=-2/3 ,x=-5/3
Find the zeros of 9x^2+21x+10=0
The zeros of 9x^2+21x+10=0 are x=-2/3 ,x=-5/3