What is factor 16a^4-b^4 ?

The solution to factor 16a^4-b^4 is (4a^2+b^2)(2a+b)(2a-b)

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factor 16a^4-b^4

factor

16 a^{4} - b^{4}

(4 a^{2} + b^{2}) (2 a + b) (2 a - b)

Solution steps

16 a^{4} - b^{4}

16 a^{4} = (4 a^{2})^{2}

b^{4} = (b^{2})^{2}

= (4 a^{2})^{2} - (b^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 a^{2})^{2} - (b^{2})^{2} = (4 a^{2} + b^{2}) (4 a^{2} - b^{2})

= (4 a^{2} + b^{2}) (4 a^{2} - b^{2})

Factor

4 a^{2} - b^{2} : (2 a + b) (2 a - b)

= (4 a^{2} + b^{2}) (2 a + b) (2 a - b)

\frac{1}{x}

x - 4 [x - 2 (x + 6)] = 5 x + 3

\frac{1}{\frac{5}{\frac{7}{8} - \frac{1}{2}}} + \frac{1}{20}

x + 1 > 6

- 27 x = 5 - 54 x

What is factor 16a^4-b^4 ?
The solution to factor 16a^4-b^4 is (4a^2+b^2)(2a+b)(2a-b)