What are the solutions to the equation p^2-10p+24=0 ?

The solutions to the equation p^2-10p+24=0 are p=6,p=4

Find the zeros of p^2-10p+24=0

The zeros of p^2-10p+24=0 are p=6,p=4

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p^{2} - 10 p + 24 = 0

p = 6, p = 4

Solution steps

p^{2} - 10 p + 24 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

p_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, p_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

p = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

p = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

p = 6, p = 4

2 (- 2)

\frac{5}{7} - \frac{3}{21}

- 45 \cdot \frac{π}{180}

\frac{1}{z + 3} < - 5

What are the solutions to the equation p^2-10p+24=0 ?
The solutions to the equation p^2-10p+24=0 are p=6,p=4
Find the zeros of p^2-10p+24=0
The zeros of p^2-10p+24=0 are p=6,p=4