What are the solutions to the equation x^2-18=3x ?

The solutions to the equation x^2-18=3x are x=6,x=-3

Find the zeros of x^2-18=3x

The zeros of x^2-18=3x are x=6,x=-3

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x^{2} - 18 = 3 x

x = 6, x = - 3

Solution steps

x^{2} - 18 = 3 x

Move

3 x

to the left side

x^{2} - 18 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 1}

x = \frac{- ( - 3 ) + 9}{2 \cdot 1} : 6

x = \frac{- ( - 3 ) - 9}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 6, x = - 3

8 x^{2} + 20 = 148

27 \cdot 3

x^{3} - x^{2} - 4 x + 4 \geq 0

∣ x - 1 ∣ = 9

20 \leq 4 x

What are the solutions to the equation x^2-18=3x ?
The solutions to the equation x^2-18=3x are x=6,x=-3
Find the zeros of x^2-18=3x
The zeros of x^2-18=3x are x=6,x=-3