What are the solutions to the equation x^2+1.5x-1=0 ?

The solutions to the equation x^2+1.5x-1=0 are x= 1/2 ,x=-2

Find the zeros of x^2+1.5x-1=0

The zeros of x^2+1.5x-1=0 are x= 1/2 ,x=-2

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x^{2} + 1.5 x - 1 = 0

x = \frac{1}{2}, x = - 2

Decimal Notation

x = 0.5, x = - 2

Solution steps

x^{2} + 1.5 x - 1 = 0

Multiply both sides by

10

10 x^{2} + 15 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 10 ( - 10 )}{2 \cdot 10}

1 5^{2} - 4 \cdot 10 (- 10) = 25

x_{1, 2} = \frac{- 15 \pm 25}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 15 + 25}{2 \cdot 10}, x_{2} = \frac{- 15 - 25}{2 \cdot 10}

x = \frac{- 15 + 25}{2 \cdot 10} : \frac{1}{2}

x = \frac{- 15 - 25}{2 \cdot 10} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 2

x^{2} - 2 x - 5 \geq x^{2} + 4 x + 1

- 2 \leq \frac{c}{2}

\frac{x + 11}{8} = - 3

3 x^{2} + 5 x \leq 2

ln \frac{k + 2}{2 + k} = 0

What are the solutions to the equation x^2+1.5x-1=0 ?
The solutions to the equation x^2+1.5x-1=0 are x= 1/2 ,x=-2
Find the zeros of x^2+1.5x-1=0
The zeros of x^2+1.5x-1=0 are x= 1/2 ,x=-2