What are the solutions to the equation (0-2)^2+(y+7)^2=9 ?

The solutions to the equation (0-2)^2+(y+7)^2=9 are y=sqrt(5)-7,y=-sqrt(5)-7

Find the zeros of (0-2)^2+(y+7)^2=9

The zeros of (0-2)^2+(y+7)^2=9 are y=sqrt(5)-7,y=-sqrt(5)-7

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(0 - 2)^{2} + (y + 7)^{2} = 9

y = 5 - 7, y = - 5 - 7

Decimal Notation

y = - 4.76393 \dots, y = - 9.23606 \dots

Solution steps

(0 - 2)^{2} + (y + 7)^{2} = 9

Move

(0 - 2)^{2}

to the right side

(y + 7)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 7 = 5 : y = 5 - 7

Solve

y + 7 = - 5 : y = - 5 - 7

The solutions to the quadratic equation are:

y = 5 - 7, y = - 5 - 7

9 y^{2} - 30 y + 25

6 x^{3} - 11 x^{2} - 10 x

(x y)^{3}

314

6 - 4 x \geq 30

What are the solutions to the equation (0-2)^2+(y+7)^2=9 ?
The solutions to the equation (0-2)^2+(y+7)^2=9 are y=sqrt(5)-7,y=-sqrt(5)-7
Find the zeros of (0-2)^2+(y+7)^2=9
The zeros of (0-2)^2+(y+7)^2=9 are y=sqrt(5)-7,y=-sqrt(5)-7