What are the solutions to the equation 2x*(1-x)=x-6 ?

The solutions to the equation 2x*(1-x)=x-6 are x=-3/2 ,x=2

Find the zeros of 2x*(1-x)=x-6

The zeros of 2x*(1-x)=x-6 are x=-3/2 ,x=2

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2 x \cdot (1 - x) = x - 6

x = - \frac{3}{2}, x = 2

Decimal Notation

x = - 1.5, x = 2

Solution steps

2 x (1 - x) = x - 6

Expand

2 x (1 - x) : 2 x - 2 x^{2}

2 x - 2 x^{2} = x - 6

Move

6

to the left side

2 x - 2 x^{2} + 6 = x

Move

x

to the left side

- 2 x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 6 = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 ( - 2 )}, x_{2} = \frac{- 1 - 7}{2 ( - 2 )}

x = \frac{- 1 + 7}{2 ( - 2 )} : - \frac{3}{2}

x = \frac{- 1 - 7}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 2

6 x + 10 > 5 x - 12

6 x^{2} - 6 x - 36 = 0

4 b + 3 = - 9

14 x - 10 = 4

What are the solutions to the equation 2x*(1-x)=x-6 ?
The solutions to the equation 2x*(1-x)=x-6 are x=-3/2 ,x=2
Find the zeros of 2x*(1-x)=x-6
The zeros of 2x*(1-x)=x-6 are x=-3/2 ,x=2