What are the solutions to the equation 4x^2+17x+4=0 ?

The solutions to the equation 4x^2+17x+4=0 are x=-1/4 ,x=-4

Find the zeros of 4x^2+17x+4=0

The zeros of 4x^2+17x+4=0 are x=-1/4 ,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 17 x + 4 = 0

x = - \frac{1}{4}, x = - 4

Decimal Notation

x = - 0.25, x = - 4

Solution steps

4 x^{2} + 17 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

1 7^{2} - 4 \cdot 4 \cdot 4 = 15

x_{1, 2} = \frac{- 17 \pm 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 17 + 15}{2 \cdot 4}, x_{2} = \frac{- 17 - 15}{2 \cdot 4}

x = \frac{- 17 + 15}{2 \cdot 4} : - \frac{1}{4}

x = \frac{- 17 - 15}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - 4

1 - 2 x \geq 3

\frac{2 x}{5} = \frac{9}{15}

4 x^{2} + 5 x - 1 = 0

4 x = x + 2

2 (x + 4) - 3 < 15

What are the solutions to the equation 4x^2+17x+4=0 ?
The solutions to the equation 4x^2+17x+4=0 are x=-1/4 ,x=-4
Find the zeros of 4x^2+17x+4=0
The zeros of 4x^2+17x+4=0 are x=-1/4 ,x=-4