What is factor b^3-4b^2-16b+64 ?

The solution to factor b^3-4b^2-16b+64 is (b-4)^2(b+4)

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factor b^3-4b^2-16b+64

factor

b^{3} - 4 b^{2} - 16 b + 64

(b - 4)^{2} (b + 4)

Solution steps

b^{3} - 4 b^{2} - 16 b + 64

= (b^{3} - 4 b^{2}) + (- 16 b + 64)

Factor out

b^{2}

from

b^{3} - 4 b^{2} : b^{2} (b - 4)

Factor out

- 16

from

- 16 b + 64 : - 16 (b - 4)

= b^{2} (b - 4) - 16 (b - 4)

Factor out common term

b - 4

= (b - 4) (b^{2} - 16)

Factor

b^{2} - 16 : (b + 4) (b - 4)

= (b - 4) (b + 4) (b - 4)

Apply exponent rule:

aa = a^{2}

(b - 4) (b - 4) = (b - 4)^{2}

= (b - 4)^{2} (b + 4)

\frac{4 - 2 x}{x ^{2} + 2} > 2 - \frac{x}{x - 3}

r^{2} = - 3 r + 4

10 + 3 k \leq 22

lo g_{4} (x) < 4

9 v^{2} - 12 v + 4

What is factor b^3-4b^2-16b+64 ?
The solution to factor b^3-4b^2-16b+64 is (b-4)^2(b+4)