What is factor 8n^4+24n^3-n-3 ?

The solution to factor 8n^4+24n^3-n-3 is (n+3)(2n-1)(4n^2+2n+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 8n^4+24n^3-n-3

factor

8 n^{4} + 24 n^{3} - n - 3

(n + 3) (2 n - 1) (4 n^{2} + 2 n + 1)

Solution steps

8 n^{4} + 24 n^{3} - n - 3

= (8 n^{4} + 24 n^{3}) + (- n - 3)

Factor out

8 n^{3}

from

8 n^{4} + 24 n^{3} : 8 n^{3} (n + 3)

Factor out

- 1

from

- n - 3 : - (n + 3)

= 8 n^{3} (n + 3) - (n + 3)

Factor out common term

(n + 3) : (n + 3) (8 n^{3} - 1)

= (n + 3) (8 n^{3} - 1)

Factor

8 n^{3} - 1 : (2 n - 1) (2^{2} n^{2} + 2 n + 1)

= (n + 3) (2 n - 1) (2^{2} n^{2} + 2 n + 1)

2^{2} = 4

= (n + 3) (2 n - 1) (4 n^{2} + 2 n + 1)

\frac{4}{3} - \frac{3}{4}

- 3 x \leq 9

\frac{π}{\frac{2}{6}}

x^{4} - 2 x^{2} - 8

w^{2} + 8 w = 2

What is factor 8n^4+24n^3-n-3 ?
The solution to factor 8n^4+24n^3-n-3 is (n+3)(2n-1)(4n^2+2n+1)