What are the solutions to the equation 7x^2=-x ?

The solutions to the equation 7x^2=-x are x=0,x=-1/7

Find the zeros of 7x^2=-x

The zeros of 7x^2=-x are x=0,x=-1/7

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7 x^{2} = - x

x = 0, x = - \frac{1}{7}

Solution steps

7 x^{2} = - x

Move

x

to the left side

7 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

1^{2} - 4 \cdot 7 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 7}, x_{2} = \frac{- 1 - 1}{2 \cdot 7}

x = \frac{- 1 + 1}{2 \cdot 7} : 0

x = \frac{- 1 - 1}{2 \cdot 7} : - \frac{1}{7}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{7}

x^{2} + 3 x - 1 = 3

3 y^{2} + 19 y + 6

2 m^{4} - 32

\frac{b - 1}{4} + \frac{2 b - 5}{3} = \frac{5 b}{6}

0.16

What are the solutions to the equation 7x^2=-x ?
The solutions to the equation 7x^2=-x are x=0,x=-1/7
Find the zeros of 7x^2=-x
The zeros of 7x^2=-x are x=0,x=-1/7