What are the solutions to the equation x^2=-245 ?

The solutions to the equation x^2=-245 are x=sqrt(5)*7i,x=-sqrt(5)*7i

Find the zeros of x^2=-245

The zeros of x^2=-245 are x=sqrt(5)*7i,x=-sqrt(5)*7i

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x^{2} = - 245

x = 5 \cdot 7 i, x = - 5 \cdot 7 i

Solution steps

x^{2} = - 245

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 245, x = - - 245

- 245 = 5 \cdot 7 i

- - 245 = - 5 \cdot 7 i

x = 5 \cdot 7 i, x = - 5 \cdot 7 i

x^{3} - x \leq 0

∣ 2 x + 3 ∣ \geq 5

- 3 (3 y - 2) < 1 - 9 y

\frac{r}{5} = \frac{4}{7}

9 x^{4} - 75 x^{3} + 126 x^{2}

What are the solutions to the equation x^2=-245 ?
The solutions to the equation x^2=-245 are x=sqrt(5)*7i,x=-sqrt(5)*7i
Find the zeros of x^2=-245
The zeros of x^2=-245 are x=sqrt(5)*7i,x=-sqrt(5)*7i