What are the solutions to the equation 5x^2+1=26 ?

The solutions to the equation 5x^2+1=26 are x=sqrt(5),x=-sqrt(5)

Find the zeros of 5x^2+1=26

The zeros of 5x^2+1=26 are x=sqrt(5),x=-sqrt(5)

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5 x^{2} + 1 = 26

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

5 x^{2} + 1 = 26

Move

1

to the right side

5 x^{2} = 25

Divide both sides by

5

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

3 + ∣ 8 + 5 x ∣ = 10

∣ 3 x - 8 ∣ - 1 \geq 3

3 q + 6 = 19

(2 l)^{2} - 4 (l + 2) (l - 1) > 0

2 x^{2} - 2 x - 6

What are the solutions to the equation 5x^2+1=26 ?
The solutions to the equation 5x^2+1=26 are x=sqrt(5),x=-sqrt(5)
Find the zeros of 5x^2+1=26
The zeros of 5x^2+1=26 are x=sqrt(5),x=-sqrt(5)