What are the solutions to the equation x^2+(2/5)^2=1 ?

The solutions to the equation x^2+(2/5)^2=1 are x=(sqrt(21))/5 ,x=-(sqrt(21))/5

Find the zeros of x^2+(2/5)^2=1

The zeros of x^2+(2/5)^2=1 are x=(sqrt(21))/5 ,x=-(sqrt(21))/5

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x^{2} + (\frac{2}{5})^{2} = 1

x = \frac{21}{5}, x = - \frac{21}{5}

Decimal Notation

x = 0.91651 \dots, x = - 0.91651 \dots

Solution steps

x^{2} + (\frac{2}{5})^{2} = 1

Expand

x^{2} + (\frac{2}{5})^{2} : x^{2} + \frac{4}{25}

x^{2} + \frac{4}{25} = 1

Move

\frac{4}{25}

to the right side

x^{2} = 1 - \frac{4}{25}

Simplify

1 - \frac{4}{25} : \frac{21}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{21}{25}, x = - \frac{21}{25}

\frac{21}{25} = \frac{21}{5}

- \frac{21}{25} = - \frac{21}{5}

x = \frac{21}{5}, x = - \frac{21}{5}

2 \leq x + 8 < 6

(18 + x) 2 = 30

\frac{1}{4} e^{2}

5 x - 19 < 16

7 x - 4 = 6 x

What are the solutions to the equation x^2+(2/5)^2=1 ?
The solutions to the equation x^2+(2/5)^2=1 are x=(sqrt(21))/5 ,x=-(sqrt(21))/5
Find the zeros of x^2+(2/5)^2=1
The zeros of x^2+(2/5)^2=1 are x=(sqrt(21))/5 ,x=-(sqrt(21))/5